This is a bit complex method and very ineffective, but if some one can create a software for this, this can work very well

This is what i foud

suppose there are 20 users in the room and an admin

if u use choman spy and view the user list ull find 20 users , if u use sjboy and go to open chat rooms....ect, ull see that there are 21 users

so there is a 1 user gap
THAT MEANS THERE IS SOME ONE HIDING

SO PPL i tld u this is a ineffective way, but if some one can do a small programming,(to count this in a regular interval and find if there is a gap or not i think we can comeup with somethig

tanks moonty250 for info....

thanks for info..

thank 4 dat post

thankzz now we can know there is somebody hidding... but the problem is we never know who r they

@maistro,Just click on 'enter username' and write his/her id

Thats the problem, only admin can hide their status, try to greet that hiding admin, if he/she answer u, then no more hide and seek

Tidus wrote:Thats the problem, only admin can hide their status, try to greet that hiding admin, if he/she answer u, then no more hide and seek

lolz. :p no way to find it

Tidus have a point finding an admin in the rum is hard nowdays

ow gitu toh... thanks info ne

thanks for ur info